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3 years ago

Please can someone help me out

Mathematics

2 answers:

mina [271]3 years ago

6 0

Answer:

A≈153.94cm²

Step-by-step explanation:

the internet told me personally

Rasek [7]3 years ago

5 0

Answer:

153.938040026

Step-by-step explanation:

7 x 7 = 49

49 x pi = 153.938040026

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Find one value of xxx that is a solution to the equation (2x+3) 2 −6x−9=0

vesna_86 [32]

(2x+3) ^2 −6x−9=0

(2x+3) (2x+3) −6x−9=0

Foil

4x^2 +6x+6x+9-6x-9=0

4x^2 +12x+9-6x-9=0

Combine like terms

4x^2 +6x=0

factor out 2x

2x(2x+3)=0

2x=0 2x+3=0

x=0 2x=-3

x=-3/2

Answer x=-3/2, 0

3 0

3 years ago

Helpppppppp a mate out ;-;

svetlana [45]

For ∆RNM ~ ∆RPQ
=> RN/RP = RM/RQ
=> 7/8 = 10/14 which is wrong
So ∆RMN is not similar to ∆RQP

5 0

3 years ago

Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it

Novay_Z [31]

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

$z^{2}=\frac{Ak}{Aj}$

we have

$z=4$

substitute

$4^{2}=\frac{Ak}{Aj}$

$16=\frac{Ak}{Aj}$

$Ak=16Aj$

therefore

The area of triangle K is 16 times greater than the area of triangle J

4 0

3 years ago

Read 2 more answers

Solve for X. x+3 4 8

m_a_m_a [10]

Answer:

First find the hypotenuse of the small triangle then use that value as the base of the upper triangle. Evaluate the equation formed with the “x"

8 0

3 years ago

Can someone please give me the (Answers) to this? ... please ... I need help….

lesya692 [45]

Answer:

above is the answer to the question, second picture for clear view

8 0

3 years ago

Please can someone help me out​

Please can someone help me out