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2 years ago

What's the midpoint of (-10,3) and (0,9)

Mathematics

1 answer:

Zepler [3.9K]2 years ago

3 0

Answer:

To find the midpoint we need to find the point which is the same distance between the x and y values in both points. For example the distance to a point that will be shared among the 2 x's is -5. -10 (x1) and 0 (second x value) are both 5 units away from -5. to -5 is the x of our new point: (-5, y)

Now do the same for the y value:

9-3=6

6 is the y value of our new point

(-5, 6) is your answer

Hoped this helped!

Step-by-step explanation:

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Is 1/2 is equal to 1/10+1/10+1/10+1/10+1/10?

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Answer:

Yes

Step-by-step explanation:

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3 years ago

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4 bottles of water cost 10 dollars at a music festival.

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Answer:

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Step-by-step explanation:

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2 years ago

Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

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2 years ago

What does x equal? <br> Thanks!

11Alexandr11 [23.1K]

Answer: 33 degrees

Step-by-step explanation:

See paper attached. (: