Answer:
B. It is reasonable to use the? z-interval procedure in this case? since, although the sample is small? (size less than? 15), the variable under consideration is very close to being normally distributed.
Step-by-step explanation:
answer b is considered to be correct because we know that the population is normal and the standard deviation is known, which allows using the interval z, the answer A is not correct because although the option to use the interval z is given, which is correct, the large sample is not favored, the answer C and D are incorrect because they both reject the use of the z interval and in d it is further rejected that although there is a normal distribution the sample is not, which is false
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
Referring to a standard normal distribution table, and using z = 0.66, we find:
Therefore
The answer is: 0.2546
Qt = 16.
Because since rs Is equal to qr since r is the midpoint of qs. So qr is 8 and because s is the midpoint of the whole line. I multiply it by 2. Giving me 16 for the whole line
Answer:
Find the exact value using trigonometric identities. a MP3, 45, 0.15
Step-by-step explanation:
so your answer is $45.15 that is how much it was before the discount :)
Answer:
7x−3=7k,x=7k+3,k∈ℤ
Step-by-step explanation:
3x ≡ 2 (mod 7)
3 is a solution, since 3×3−2=7.
All solutions are 3+7ℤ
y=3x−2/7=3(x−3)+7/7=3(x−3)/7+1
7x−3=7k,x=7k+3,k∈ℤ
