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anastassius [24]
3 years ago
15

Ratna wrote that X plus X plus X is equivalent to X to the third power what error did she make

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0
Usually when talking about powers the numbers or variables are multiplied but Ratna added instead.
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Solution for: <br> -x + 3y -2z = 19<br> 2x + y - z = 5<br> -3x - y + 2z = -7
STatiana [176]

Answer:

x = -1 , y = 4 , z = -3

Step-by-step explanation:

Solve the following system:

{-x + 3 y - 2 z = 19 | (equation 1)

2 x + y - z = 5 | (equation 2)

-3 x - y + 2 z = -7 | (equation 3)

Swap equation 1 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

2 x + y - z = 5 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Add 2/3 × (equation 1) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y/3 + z/3 = 1/3 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Multiply equation 2 by 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Subtract 1/3 × (equation 1) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+(10 y)/3 - (8 z)/3 = 64/3 | (equation 3)

Multiply equation 3 by 3/2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+5 y - 4 z = 32 | (equation 3)

Swap equation 2 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+y + z = 1 | (equation 3)

Subtract 1/5 × (equation 2) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+(9 z)/5 = (-27)/5 | (equation 3)

Multiply equation 3 by 5/9:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add 4 × (equation 3) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y+0 z = 20 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by 5:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add equation 2 to equation 1:

{-(3 x) + 0 y+2 z = -3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(3 x)+0 y+0 z = 3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by -3:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer:  {x = -1 , y = 4 , z = -3

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3 years ago
How many unique ways are there to arrange the letters in the word error
quester [9]
They can be arranged 120 different ways
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Dave has a three-year college loan for $10,000. The lender charges a simple interest rate of 6 percent. How much interest will h
PSYCHO15rus [73]
I= 10000*3*0.06 I=1800
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3 years ago
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Two chemicals X and Y are to be mixed together to achieve a 16ml solution that is 7.4% water. Chemical x is 5% water and Y is 9%
makvit [3.9K]

Answer:

9.6 mL

Step-by-step explanation:

If x is mL of chemical X, and y is mL of chemical Y, then:

x + y = 16

0.05x + 0.09y = 0.074(16)

Solve the system of equations using substitution.

0.05(16 − y) + 0.09y = 0.074(16)

0.8 − 0.05y + 0.09y = 1.184

0.04y = 0.384

y = 9.6

You need 9.6 mL of Y.

8 0
3 years ago
At 2:00 p.m., Brandon said it was 10°C. Eight hours later, Brandon said the temperature dropped 18°C. What
S_A_V [24]
The answer is B -8°C
hoped it helped!
4 0
3 years ago
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