Answer:
10m15n10
Step-by-step explanation:
5x2m=10m
5x3n=15n
5x2=10
so you get 10m15n10
you can't simplify it anymore because none of them have the same variables
Answer:
Step-by-step explanation:
1/10 * 1/4 = 1/14
1/2 because there is a 50/50% chance its either heads or tails
Answer:
122+42x= 2( 61+21x)
4x+16x+24 = 4(5x+6)
24x+48-3x = 21x+48
3x+39-2x = x+29
Step-by-step explanation:
ANSWER
5
EXPLANATION
The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is
![h(t) = - 4.9 {t}^{2} + 25t](https://tex.z-dn.net/?f=h%28t%29%20%3D%20%20-%204.9%20%7Bt%7D%5E%7B2%7D%20%20%2B%2025t)
To find the time when the ball hit the ground,we equate the function to zero.
![- 4.9 {t}^{2} + 25t = 0](https://tex.z-dn.net/?f=%20-%204.9%20%7Bt%7D%5E%7B2%7D%20%20%2B%2025t%20%3D%200)
Factor to obtain;
![t( - 4.9t + 25) = 0](https://tex.z-dn.net/?f=t%28%20-%204.9t%20%2B%2025%29%20%3D%200)
Apply the zero product property to obtain,
![t = 0 \: or \: \: - 4.9t + 25 = 0](https://tex.z-dn.net/?f=t%20%3D%200%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20-%204.9t%20%2B%2025%20%3D%200)
![t = 0 \: \: or \: \: t = \frac{ - 25}{ - 4.9}](https://tex.z-dn.net/?f=t%20%3D%200%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20t%20%3D%20%20%5Cfrac%7B%20-%2025%7D%7B%20-%204.9%7D%20)
t=0 or t=5.1 to the nearest tenth.
Therefore the ball hits the ground after approximately 5 seconds.
Answer: 3t-8
Step-by-step explanation:
<em>3t-8 is the answer because there are no like terms.</em>
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