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2 years ago

Which equation below describes the hanger?

Mathematics

1 answer:

muminat2 years ago

8 0

9514 1404 393

Answer:

D. 12 = 2 * y

Step-by-step explanation:

On one side is 12.

On the other side is y + y = 2y.

This sort of "hanger" represents the equation that sets one side equal to the other:

12 = 2y

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Do you think making a table is the best way to find the total area of the rooms

Komok [63]

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3 years ago

Carl and Tamera want to compare their tests in math class. They have taken six tests. Should they use the mean, median or mode t

Roman55 [17]

Answer:

Mean

Step-by-step explanation:

I said mean because it would allow both Carl and Tamera to average their scores and compare one side by side rather than comparing 6 each which would just be time consuming and it seems like it wouldn't be any other choices.

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2 years ago

Dy/dx ln(xy)=e^(x+y)

Westkost [7]

In(xy) = e^(x+y)

(xy)'/xy = (x+y)' e^(x+y)

(x'y + xy')/xy = (1+y') e^(x+y)

(y + xy')/xy = (1+y')e^(x+y) and simplify

Hope this helps

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2 years ago

Help plz with this question. Needed fast. I will mark brainliest.

vodomira [7]

Answer:

≈ 68.2°

Step-by-step explanation:

tan X= 20/8

tan X= 2.5

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2 years ago

Read 2 more answers

Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i

Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1

Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

3 0

3 years ago