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Fed [463]
3 years ago
7

I need help, don't get it ​

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer:

\sqrt[3]{2y}  = 6 - 4

2y=2³

2y=8

<em><u>y=4</u></em>

Firdavs [7]3 years ago
5 0

Answer:

it is 500 hope this helps

Step-by-step explanation:

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What is the graph of y = x2 + 6x + 13 ?<br> What does the graph look like
ladessa [460]

Answer:

If I entered it in correctly it would look something like this,,

7 0
3 years ago
There are 84 boys in the 6th grade class. If boys make up 30% of the 6th graders, how many students are in this whole 6th grade
koban [17]
<h3>Answer:  280</h3>

Work Shown:

x = number of students in the 6th grade class

30% = 30/100 = 0.30

30% of x = 0.30x this is equal to 84 since "30% of the 6th graders are boys (and there are 84 boys in sixth grade)", so we say 0.30x = 84

Divide both sides by 0.30 to isolate x

0.30x = 84

0.30x/0.30 = 84/0.30

x = 280

So there are 280 students overall in the 6th grade class.

7 0
4 years ago
Read 2 more answers
2 Points
nadezda [96]

Answer:

x^2 +4x -4      

Step-by-step explanation:

f(x) = 4x + 1 and g(x) = x^2 - 5

(f+ g)(x) =  4x + 1 + x^2 - 5

Combine like terms

          = x^2 +4x -4      

4 0
4 years ago
If sin A = 11/61 find tan A , Cos A and Sec A
Nimfa-mama [501]

Answer:tanA=11/60 cosA=60/61 secA=61/60

Step-by-step explanation:

From Pythagoras rule (adjacent)=√(61^2-11^2)

Adjacent=√(3721-121)

Adjacent=√(3600) adjacent=60

Opposite=11 hypotenuse=61 adjacent=60

TanA=11/60 cosA=60/61 secA=61/60

4 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 12 centered at the point (−3, 0). Use the polygon tool to
kaheart [24]

Answer:

See attached

Step-by-step explanation:

For some point X, center C, and dilation factor k, the image point X' will be ...

... X' = C + k(X -C)

Assuming you want k=12 in both cases, for the written problem, the first point is ...

... X' = (-3, 0) + 12((-5, 4) -(-3, 0)) = (-3, 0) +12(-2, 4)

... = (-3, 0) +(-24, 48)

... X' = (-27, 48)

_____

In the problem in the image, the lower right point will be ...

... Q' = C + k(Q -C)

... Q' = (-3, 1) +12((2, 2) -(-3, 1)) = (-3, 1) + 12(5, 1)

... = (-3, 1) + (60, 12)

... Q' = (57, 13)

4 0
4 years ago
Read 2 more answers
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