Rolling a 4 on a six-sided die with its expected probability?
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We assume that the dimension 5 has units of feet.
The area of each triangle will be
A = (1/2)bh
where b=2×(5 ft), h=(5 ft)tan(54°)
Then
A = (1/2)(2×5 ft)(5 ft)(tan(54°)
A = 25×tan(54°) ft²
There are 5 such triangles making up this pentagon, so the total area is
total area = 5×25×tan(54°) ft² ≈ 172 ft²
The area of each triangle will be
A = (1/2)bh
where b=2×(5 ft), h=(5 ft)tan(54°)
Then
A = (1/2)(2×5 ft)(5 ft)(tan(54°)
A = 25×tan(54°) ft²
There are 5 such triangles making up this pentagon, so the total area is
total area = 5×25×tan(54°) ft² ≈ 172 ft²