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max2010maxim [7]
3 years ago
11

A turtle can swim 20 meters in 4 seconds. At this rate, how many meters can the turtle swim in 10 minutes?

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

3,000 meters

Step-by-step explanation:

10*60=600/4=150*20=3000 meters (I highly doubt a turtle can swim three kilometers in 10 min... especially if it's a box turtle).

You might be interested in
2.5 X 10^5 divided by 1.0 X 10^10
bekas [8.4K]

Answer:

0.000025

Step-by-step explanation:

PEMDAS (Exponets first.)

10^5 = 100,000

10^10 = 10,000,000,000

rewrite

2.5 x 100,000 divided by 1.0 x 10,000,000,000

PEMDAS (multiplication next.)

2.5 x (10^5) = 250,000

1.0 x (10^10) = 10,000,000,000

rewrite.

250,000 divided by 10,000,000,000 = 0.000025

0.000025

6 0
3 years ago
In 5 minutes, Joey eats 25 hot dogs. how many hot dogs did he eat in a minute?​
Colt1911 [192]
Answer: He Had 5 Per Min.

25 ÷ 5 = 5

5 Per Min.
4 0
3 years ago
Read 2 more answers
The perimeter of the isoceles triangle is 54. The ratio of the leg to the base is 7:4. Find the length of the base
Norma-Jean [14]

9514 1404 393

Answer:

  12 units

Step-by-step explanation:

The ratio of the base to the other sides is ...

  4 : 7 : 7

The perimeter is a total of 4 +7 +7 = 18 ratio units, so each ratio units stands for 54/18 = 3 length units.

The base length is then ...

  (4 ratio units)(3 length units/ratio unit) = 12 length units

4 0
2 years ago
Solving Graphically...<br>PLEASE HELP
olasank [31]
Infinitely many? Arrows indicate that the graph goes on continuously without a stopping point, even in parabolas.
3 0
3 years ago
Hey everyone !
zhuklara [117]

Answer:

The measure of the largest angle is 120°

Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

 to angle A is BC , the side opposite to angle B is AC and the side

 opposite to angle C is AB, So to find measure of angle A use the rule

 cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

 AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}

∴ cos(C)=\frac{36+100-196}{120}

∴ cos(C)=\frac{-60}{120}=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C = cos^{-1}(-0.5)=120

* <em>The measure of the largest angle is 120°</em>

8 0
2 years ago
Read 2 more answers
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