3 is 93 and 4 is -18 i hope this helped
60
2 and 30
30
2 and 15
15
3 and 5
96
8 and 12
circle for 8 is 2 and the square is 4
circle for 12 is 2 and the last circle is also 2
Given:
The points are (-3, 2) and (2, -13).
To find:
Slope-intercept form of the equation.
Solution:
Here
.
Slope of the line:



m = -3
Using point-slope formula:




Add 2 on both sides.


Slope-intercept form of the equation is y = -3x - 7.