Answer:
15.7
Step-by-step explanation:
Lets take a = 50.
Area of Sector =

Answer:
m+2e=330
3m+1e=515
use simultaneous formula to get
m=37
e=146.5
Since the perimeter must not exceed 291.
Let the third side be x.
x + 87 + 64 < 291
x + 151 < 291.
x < 291 -151.
x < 140. (First)
But for a triangle there is what is called the Triangle Inequality Theorem. That given the two sides of a tringle, the third side of the triangle must greater than the positive difference between the two sides and less than the sum of the two sides.
So for this case. 87 and 64.
x > ( 87 - 64). x > 23.
x < (87 + 64) x < 151. Combine both inequalities.
23 < x < 151 (second).
Combining First and second. Both must be satisfied.
So we have a more accurate answer as:
23 < x < 140. x is greater than 23 and x is less than 140.
x could be 24, 25, 26, 27, ......, 139. cm.
I hope this helps.
68-40=28
28/4=7
therefore, 7 is your answer
(Hope it helps my friend ^_^)
Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Part 5)
Part 6) The graph in the attached figure
Step-by-step explanation:
Part 1) we have


The equation of the line into point slope form is equal to

substitute



Part 2) we know that
If two lines are perpendicular
then
the product of their slopes is equal to minus one
so

the slope of the line 1 is equal to

Find the slope m2


Find the equation of the line 2
we have


The equation of the line into point slope form is equal to

substitute



Part 3) we have

The equation of the line into point slope form is equal to

substitute



Part 4) we have

-----> y-intercept
we know that
The equation of the line into slope intercept form is equal to

substitute the values

Part 5) we have that
The slope of the line 4 is equal to 
so
the slope of the line perpendicular to the line 4 is equal to

therefore
in this problem we have


The equation of the line into point slope form is equal to

substitute



Part 6)
using a graphing tool
see the attached figure