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miv72 [106K]
3 years ago
5

Please help. I’ve been here for hours and no one wants to help. I’ll give brainliest answer :(

Mathematics
1 answer:
irakobra [83]3 years ago
5 0

1. D

2. J

3. L

4. A

5. B

6. K

7. C

8. I

9. F

10. G

Radius = Center to Perimeter of Circle

Minor Arc = Arc that goes around less than 1/2 of circle

Major Arc = Arc that goes around more than 1/2 of circle

Chord = The straight line segment between 2 points on a circle

Secant = A line that passes through 2 points on a circle

Semicircle = 1/2 Circle

Tangent = Line that touches 1 point on a circle's perimeter

Central Angle = Angle with a vertex at the center of a circle

Inscribed Angle = Angle whose 3 points (vertex & 2 other points) are on the outside of the circle

Right Angle = Angle with 90 degree measure

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What ? answer? dont know which one

5 0
3 years ago
2x - 4 = 2(x - 2)<br> solve the following problem and identify the type of equation
Sergio [31]

Answer:

6

Step-by-step explanation:

8 0
3 years ago
If the subspace of all solutions of Ax 0 has a basis consisting of vectors and if A is a ​matrix, what is the rank of​ A
Nuetrik [128]

Question: If the subspace of all solutions of

Ax = 0

has a basis consisting of vectors and if A is a ​matrix, what is the rank of​ A.

Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.

Assume: The number of vectors is 3, and the dimension is 5 × 8.

Answer:

The rank of the matrix A is 5.

Step-by-step explanation:

In the standard basis of the linear transformation:

f : R^8 → R^5, x↦Ax

the matrix A is a representation.

and the dimension of kernel of A, written as dim(kerA) is 3.

By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.

That is:

rank(A) = dim(R^8) - dim(kerA)

= 8 - 3

= 5

4 0
3 years ago
ABCD is a rectangle ,its diagonals meet at O.If AO = 5x+1 and BO = 4x+9,find the length of the diagonals .(lengths in cm).
Sergeu [11.5K]

Answer:

82 cm

Step-by-step explanation:

In rectangles diagonals are equal and bisect each other

AO = BO

5x + 1 = 4x + 9

Subtract 1 from  both sides

5x  = 4x + 9 -1

5x = 4x + 8

Subtract 4x from both the sides

5x - 4x = 8

x = 8

AO = 5x + 1

     = 5*8  +1

     = 40 + 1

AO= 41 cm

Diagonal = 2*41 = 82 cm

7 0
3 years ago
Graph the line using a point and a slope. Write the equation of each line. A line that passes through the point (0, –3) and para
kiruha [24]
Y + 3 = 1.2(x - 0)

y + 3 = 1.2x - 0

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3 years ago
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