Answer:
- <u>200,000</u><em> 6-digit numbers can be constructed.</em>
Explanation:
Since the number is greater than 600,000, the first digit must be 6, 7, 8, or 9, so 4 different options: 4
The second, third, fourth, and fith digits can be either number 0 through 9, so 10 options for each one: 10 × 10 × 10 × 10.
Since the number must be odd and greater than 600,00, the last digit is odd, so it can be 1, 3, 5, 7, or 9, so 5 different options: 5.
Using the multiplication counting principle, you muliply the independent options to obtain the number of different combinations:
- 4 × 10 × 10 × 10 × 10 × 5 = 200,000.
whenever we have an amount to be divided in ratios, we simply divide the total amount by the sum of those ratios and then distribute accordingly. In this case, let's divide 77.40 by (1+3+5) and then distribute accordingly to each chap.
Answer:
1
Step-by-step explanation:
a*log(b) = log(b^a), so (1/2)*log(196)=log(14)
So 1+log(15)-log(14)=1
Answer:
21 is the answer your welcome