The GCF of those numbers is 2
The formula for obtaining the value of a term of a sequence is given as a
as a recursive formula.
Responses:
- The information as a sequence is; R1, 2·R1, 4·R1, 8·R1, 16·R1, ...
- The sequence of the information is a geometric sequence
<h3>How is the given information expressed as a sequence?</h3>
The amount of pocket money Smith gets = 2 × The amount he gets in the previous day
The amount Smith gets on the first day = R1
Required:
The given information expressed as a sequence.
Solution:
The amount of money smith gets can be expressed as follows;
Amount he gets on day 1 = R1
On day 2, R2 = 2·R1
On day 3, R3 = 2·R2 = 2·2·R1 = 4·R1
On day 4, R4 = 2·R3 = 2·2·2·R1 = 8·R1
On day 5, R5 = 2·R4 = 2·2·2·2··R1 = 16·R1
The information written as a sequence is therefore;
- R1, 2·R1, 4·R1, 8·R1, 16·R1, ...
- The type of sequence is a<u> geometric sequence, or progression</u> where the first term is R1, and the common ratio, r = 2
Learn more about geometric sequence here:
brainly.com/question/4289731
brainly.com/question/1532378
F(x) = 2x² + 7x - 5
g(x) = -8x² - 3x + 5
g(x) + f(x) = -8x² - 3x + 5 + 2x² + 7x - 5 = - 6x² + 4x
Answer: -6x² + 4x
To solve this problem, you have to know these two special factorizations:
Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:
![\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2Bh%7D%3Dx%5C%5C%20%5Csqrt%5B3%5D%7Bx%7D%3Dy%20)
That tells us that we have:
So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:
So, we have:
![\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2Bh-h%7D%7Bh%28%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%29%7D%3D%5C%5C%20%5Cfrac%7Bx%7D%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%20)
That is our rational expression with a rationalized numerator.
Also, you could just mutiply by:
![\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx_h%7D-%5Csqrt%5B3%5D%7Bx%7D%7D%20%5Ctext%7B%20to%20get%7D%5C%5C%20%5Cfrac%7B1%7D%7Bh%5Csqrt%5B3%5D%7Bx%2Bh%7D-h%5Csqrt%5B3%5D%7Bh%7D%7D%20)
Either way, our expression is rationalized.
