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3 years ago

PLZ HURRYYY 15 Points!!

1 answer:

5 0

Slope = (5 + 1)/(-1 - 1) = 6/-2 = -3
y = mx + b
b = y - mx
b = 5 - (-3)(-1)
b = 5 - 3
b = 2
<span>
equation of line in slope-intercept form

y = -3x + 2

hope it helps</span>

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The cross-sectional areas of a right pyramid and a right cylinder are congruent. The pyramid has a height of five units, and a r

Mazyrski [523]

Answer:

the volume of the right cylinder is 1.8 times the volume of the pyramid

Step-by-step explanation:

The volume of a pyramid is

$V = \dfrac{1}{3} \times B\times H$

where the height of the pyramid is 5

$V = \dfrac{1}{3} \times B\times 5$

$V = \dfrac{5}{3} B \ units ^3$

On the other hand, the volume of a right cylinder is

V = BH

where the height of the right cylinder = 3 units

V = 3 B units³

Since we know that the cross-sectional areas are congruent, comparing the two-volume, we have the ratio of their volumes to be:

$\dfrac{V_p}{V_c}= \dfrac{\dfrac{5}{3}B}{3B}$

$\dfrac{V_p}{V_c}= \dfrac{5}{9}$

$9 V_p = 5 V_c$

$V_c = 1.8 \ V_p$

Hence, the volume of the right cylinder is 1.8 times the volume of the pyramid

6 0

2 years ago

A soccer team has two sports coolers that hold 5 gallons each coach Fenimore has 12 fluid oz cups for the team to drink from. Ho

vesna_86 [32]

Answer:

Step-by-step explanation:

find how many fluid answers there are total, then divide by 12

3 0

2 years ago

Read 2 more answers

Can someone answer this asap?

IgorLugansk [536]

Answer:

145

Step-by-step explanation:

six can go into eight once with a remainder of two, next you bring down the seven and you will get twenty seven, six can go into twenty seven four times six by four is 24,27 take away 24 is 3 then you bring down the one, six can go into 31 five times, six by five is 30, 31 take away 30 is one

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. Given that O is the centre of the following circle, find the values of the unknowns.

alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

$a^{2} + 5^{2} = 13^{2}$

$a^{2} + 25 = 169$

$a^{2} = 169 - 25$

$a^{2} = 144$

$\sqrt{a^{2}}=\sqrt{144}$

$a = 12$

Now to find the value of 'b', i will use law of cosine,

$c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }$

$12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta = 0.3846\\\beta = cos^{-1}(0.3846)\\\beta = 67.38$

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

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