Answer:
4) VW= 23
5) VW= 12
6) VW= 75
Step-by-step explanation:
4)
VU= 31
WU= 8
subtract 8 from 31
VW= 23
5)
UW= 18
UV= 6
subtract 6 from 18
VW= 12
6)
UV= 30
WU=45
add 30 and 45
VW= 75
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer: I think the answer is B
Step-By-Step Explination:
First you find out what x is by doing 42 multiplying it by 0.1 witch equals 4.2 gallons per mile
Next you figure out what y is by doing 4.2y (witch is 4.2 times y)
<em>Refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>attachment</em>
2 x (n - 6)
(2 x n - 2 x 6)
(2n - 2 x 6)
2n - 12
