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Alona [7]
3 years ago
5

Given the table, how can you use a graph to find additional equivalent ratios? x y 2 3 4 6 Plot the ordered pairs (2, 3) and (4,

6). Start at (4, 6). Move right 3 and up 2, and then plot a point. Keep this same rate to get other points. Draw a line through the two given points. Any point below the line represents an equivalent ratio. Plot the ordered pairs (2, 4) and (3, 6). Start at (3, 6). Move right 2 and up 3, and then plot a point. Keep this same rate to get other points. Draw a line through the two given points. Any point on the line represents an equivalent ratio.
Mathematics
2 answers:
insens350 [35]3 years ago
8 0

Answer:

Sample Response:

The y-values of equivalent ratios increase at the same rate as their x-values. The vertical distance between points is constant, and the horizontal distance between points is constant. This forms a straight line.

Step-by-step explanation:

your welcome :)

Grace [21]3 years ago
4 0

Answer:

Plot the ordered pairs (2, 3) and (4, 6). Start at (4, 6). Move right 3 and up 2, and then plot a point. Keep this same rate to get other points.

Step-by-step explanation:

Dont take my for it but i think it sould be right

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3 years ago
Calculate pqrst in the diagram above showing your solutions ​
Eva8 [605]

Answer:

a. p = 6

b. q = 4

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d. s = 10; t = 8.3

Step-by-step explanation:

1. a. The side length of two similar triangles are proportional, therefore:

\frac{9}{p} = \frac{15}{10}

Cross multiply

15*p = 10*9

15*p = 90

Divide both sides by 15

p = 6

b. Based on the midsegment theorem,

q = \frac{1}{2}(8)

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c. The side length of two similar triangles are proportional, therefore:

\frac{4}{10} = \frac{r}{20}

Multiply both sides by 20

\frac{4}{10} \times 20 = \frac{r}{20} \times 20

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d. The side length of two similar triangles are proportional, therefore:

\frac{9 + 6}{9} = \frac{s}{6}

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Multiply both sides by 6

\frac{15}{9} \times 6 = \frac{s}{6} \times 6

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\frac{15}{9} = \frac{t}{5}

Multiply both sides by 5

\frac{15}{9} \times 5 = \frac{t}{5} \times 5

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