Answer:
what are the hypotheses?
Step-by-step explanation:
you said the hypotheses are as folows its not there
Answer:
The Check that hasn't been cleared yet is for $372.15.
Step-by-step explanation:
168.48+ 168.93+ 177.78+ 177.93= 693.12
887.79- 693.12= 194.67
1,065.27- 887.79= 177.48
194.67+ 177.48= 372.15
To check your answer:
372.15+ 693.12= 1,065.27
Hope this helped you!! (:
Answer:
1st option
Step-by-step explanation:
To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:
![\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%268%5C%5C3%2612%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C-14%2615%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4-2%268-1%5C%5C3-%28-14%29%2612-15%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%267%5C%5C17%26-3%5Cend%7Barray%7D%5Cright%5D)
Thus, 1st option gives the correct answer
Answer:
Ella grew 
of an inch more
Step-by-step explanation:
For this problem, you want to subtract Ben's growth from Ella's.
This expression would be 
-
.
To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).
In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by 
and the second by 
.
This makes the expression 
-
, which equals .
**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
