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alexandr402 [8]
4 years ago
6

What is 319000000 in sicentific notation?

Physics
2 answers:
kap26 [50]4 years ago
8 0
 3.19 x 10^8... hope this helps.
Reptile [31]3 years ago
8 0
The answer is:
_______________________________________________

   3.19 * 10 ⁸  .
________________________________________________
You might be interested in
Two students pushes on a box in the same direction , and one pushes In The opposite direction.what is the net force on the box i
Rufina [12.5K]

If they are both pushing with the same force but in opposite directions,
and if there are no other forces on the box besides them pushing, then
the net force on the box is zero and it just lays there, as if there were
no forces on it at all.

4 0
4 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
Nets used to catch falling boulders on the side of rocky hillside roadways
Natalija [7]

Answer:

more time to change the momentum of falling rocks

Explanation:

Momentum is related to "mass in motion." So, if an object is moving, then it has momentum as it has its mass in motion. The amount of momentum is dependent upon how much and how fast the object is moving.

If an object is moving slowly, it means that the object is losing momentum.

Nets used to catch falling boulders on the side of rocky hillside roadways  are more effective than rigid fences because their breakage is reduced by more time to change the momentum of falling rocks.

3 0
4 years ago
Rank the deformations of the following rods in terms of the magnitude of the average normal strain: (a) The length of a 1-m-long
kipiarov [429]

To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

\epsilon = \frac{\delta}{l} = \frac{l_0-l}{l}

Here,

\delta= Change in final length (l_0) and the initial length l

PART A)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{1.02-1}{1}

\epsilon = 0.01961

PART B)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{2-1.05}{2}

\epsilon = 0.475

PART C)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{3.07-3}{3}

\epsilon = 0.0233

Therefore the rank of this deformation would be  B>C>A

7 0
3 years ago
A lamp hangs vertically from a cord in a descending elevator that decelerates at 1.7 m/s2. (a) if the tension in the cord is 63
zubka84 [21]

(a)
The formula is: 
∑ F = Weight + T = mass * acceleration 

as the elevator and lamp are moving downward, I choose downward forces to be positive. 
Weight is pulling down = +(9.8 * mass) 
Tension is pulling up, so T = -63 
Acceleration is upward = -1.7 m/s^2 

(9.8 * mass) + -63 = mass * -1.7 
Add +63 to both sides 
Add (mass * 1.7) to both sides 

(9.8 * mass) + (mass * 1.7) = 63 
11.5 * mass = 63

mass = 63 / 11.5 

Mass = 5.48 kg 


(b)
Since the elevator and lamp are going upward, I choose upward forces to be positive. 
Weight is pulling down = -(9.8 * 5.48) = -53.70 
Acceleration is upward, so acceleration = +1.7 


-53.70 + T = 5.48 * 1.7

T = 53.70 + 9.316 = approx 63 N 

The Tension is still the same - 63 N since the same mass, 5.48 kg, is being accelerated upward at the same rate of 1.7 m/s^2

3 0
3 years ago
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