Plzzz help me will mark brilliant

iVinArrow [24]

(a) See graph in attachment

The appropriate graph to draw in this part is a graph of velocity vs time.

In this problem, we have a horse that accelerates from 0 m/s to 15 m/s in 10 s.

Assuming the acceleration of the horse is uniform, it means that the velocity (y-coordinate of the graph) must increase linearly with the time: therefore, the velocity-time graph will appear as a straight line, having the final point at

t = 10 s

v = 15 m/s

(b) $1.5 m/s^2$

The average acceleration of the horse can be calculated as:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 0

v = 15 m/s

t = 10 s

Substituting,

$a=\frac{15-0}{10}=1.5 m/s^2$

(c) 75 m

For a uniformly accelerated motion, the distance travelled can be calculated by using the suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance travelled

u is the initial velocity

t is the time interval

a is the acceleration

In this problem,

u = 0

t = 10 s

$a=1.5 m/s^2$

Substituting,

$s=0+\frac{1}{2}(1.5)(10)^2=75 m$

(d) See attached graphs

In a uniformly accelerated motion:

- The distance travelled (x) follows the equation mentioned in part c,

$x=ut+\frac{1}{2}at^2$

So, we see that this has the form of a parabola: therefore, the graph x vs t will represents a parabola.

- The acceleration is constant during the motion, and its value is

$a=1.5 m/s^2$ (calculated in part b)

therefore, the graph acceleration vs time will show a flat line at a constant value of 1.5 m/s^2.

6 0

3 years ago

If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when y

Readme [11.4K]

Your speed when your car hits a fixed object is 60 mph.

The given parameters:

Your initial speed, v = 60 mph

<h3>What is relative velocity?</h3>

Relative velocity tells us how fast we are traveling from a fixed point or reference point.

When travel at 60 mph in a car, you are moving at the same rate with the car.

If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.

Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.

Learn more about relative velocity here: brainly.com/question/17228388

5 0

3 years ago

An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2060 × 103 seconds (about

Fittoniya [83]

Answer:

Acceleration, $a=2.22\times 10^{-3}\ m/s^2$

Explanation:

It is given that,

Time period of revolution of the moon, $T=2060\times 10^3\ s$

If the distance from the center of the moon to the surface of the planet is, $h=235\times 10^6\ m$

The radius of the planet, $r=3.9\times 10^6\ m$

Let a is the moon's radial acceleration. Mathematically, it is given by :

$a=R\times \omega^2$ , R is the radius of orbit

Since, $\omega=\dfrac{2\pi}{T}$

The radius of orbit is,

$R=r+h$

$R=3.9\times 10^6\ m+235\times 10^6\ m=238900000\ m$

So, $a=\dfrac{4\pi^2 R}{T^2}$

$a=\dfrac{4\pi^2 \times 238900000}{(2060\times 10^3)^2}$

$a=2.22\times 10^{-3}\ m/s^2$

Hence, this is the required solution for the radial acceleration of the moon.

5 0

3 years ago

Have participles that are<br> large and that will settle out over time.

hjlf

Not a full question that can be answered sorry:/

8 0

3 years ago

How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$