Question

Factor Y4_+y2_-12 need factor of this equation

Answer 1

Answer:

y = ±√3 and ±2i

Step-by-step explanation:

Given the equation y⁴+y²-12 = 0

(y²)²+y²-12 = 0

Let P = y²

Substitute

P²+P-12 = 0

Factorize:

P²+4P-3P -12 = 0

P(P+4)-3(P+4) = 0

(P-3)(P+4) = 0

P-3 = 0 and P+4 = 0

P = 3 and -4

When P = 3

y² = 3

y = ±√3

When P = -4

y² = -4

y² = ±√-4

y = ±2i

Hence the value of y is ±√3 and ±2i