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3 years ago

Help please k(6)=?..........

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

Answer:

8.28389112 × 10-23 m2 kg s-2 K-1

Step-by-step explanation:

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Magnus wants to borrow $26,000 to remodel his kitchen. He is hoping that his monthly payment will be no more than $372. The bank

Oksi-84 [34.3K]

Answer:

About 81 months

Step-by-step explanation:

We'll have to use this formula: A = P x i(1 + i)ˣ / (1 + i)ˣ - 1

A = Montly payment (372)

P = Loan amount (26,000)

i = interest rate/12 (0.043/12 = 0.035833)

x = months (?)

372 = 26,000 x 0.035833(1 + 0.035833)ˣ / (1 + 0.035833)ˣ - 1

First, substitute (1 + 0.035833)ˣ for y just to make things easier

372 = 26,000 x 0.035833y / y - 1

Multiply both sides by y - 1

(y-1)(372 = 26,000 x 0.035833y / y - 1)

372y - 372 = 26,000 x 0.035833y

Divide both sides by y

(372y - 372)/y = (26,000 x 0.035833y)/y

372 - 372/y = 26,000 x 0.035833

Add 372/y to both sides

372 - 372/y = 26,000 x 0.035833

- 372/y - 372/y

372 = 93.1667 + 372/y

Subtract 93.1667 from both sides

372 = 93.1667 + 372/y

- 93.1667 - 93.1667

372 - 93.1667 = 372/y

Cross multiply

y = 372/(372 - 93.1667)

y = 1.33413

(1 + 0.035833)ˣ = 1.33413

log₁₋₀₀₃₅₈₃₃(1.035833ˣ) = log₁₋₀₀₃₅₈₃₃(1.33413ˣ)

x = 80.59418

7 0

2 years ago

Square root of 144 X^7 Y^5

LekaFEV [45]

The first step to solving this is to factor out the first perfect square
$\sqrt{12^{2} x^{7} y^{5} }$
now factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{5} }$
then factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{4} X y}$
the root of a product is equal to the product of the roots of each factor
$\sqrt{ 12^{2} }$ $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the first square root
12 $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the second square root
12x³ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the third square root
12x³y² $\sqrt{xy}$
this means that the correct answer to your question is 12x³y² $\sqrt{xy}$ .
let me know if you have any further questions
:)

4 0

4 years ago

What are they asking me?

morpeh [17]

Basically, they're asking you to find the slope of the given line, as well as finding how far apart each points are from one another, horizontally and vertically.

Remember, horizontal goes this way (------) and vertical goes this way (I)
(I)
(I)
a) Horizontal distance : -2
Vertical distance : 3

b) Slope :

Remember, slope is rise over run.

So, rise = vertical distance, and run = horizontal distance.

So, our slope is : -3/2

~Hope I helped!~

4 0

3 years ago

Pls answer this . I need help

madreJ [45]

Answer:

The ans is -14 if you use desmos and start "finger counting" the slope of -3, y will equal -14 once it reaches (3,y)

3 0

3 years ago

If sin θ = 3 over 7 and tan θ < 0, what is the value of cos θ?

AnnZ [28]

$if\ \sin\Theta \ \textgreater \ 0\ and\ \tan\Theta \ \textless \ 0\ then\ \Theta\in\underbrace{(90^o;\ 180^o)}_{\left(\dfrac{\pi}{2};\ \pi\right)}\\\\therefore\ \cos\Theta \ \textless \ 0.$

$\text{Use:}\ \sin^2x+\cos^2x=1\\\\\left(\dfrac{3}{7}\right)^2+\cos^2\Theta=1\\\\\dfrac{9}{49}+\cos^2\Theta=1\ \ \ |-\dfrac{9}{49}\\\\\cos^2\Theta=\dfrac{40}{49}\to\cos\Theta=-\sqrt{\dfrac{40}{49}}\\\\\cos\Theta=-\dfrac{\sqrt{40}}{\sqrt{49}}\\\\\cos\Theta=-\dfrac{\sqrt{4\cdot10}}{7}\\\\\boxed{\cos\Theta=-\dfrac{2\sqrt{10}}{7}}$

8 0

4 years ago