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erastovalidia [21]
2 years ago
10

Pls answer this . I need help

Mathematics
1 answer:
madreJ [45]2 years ago
3 0

Answer:

The ans is -14 if you use desmos and start "finger counting" the slope of -3, y will equal -14 once it reaches (3,y)

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What is the value of x?​
LiRa [457]

Answer:

98°

Step-by-step explanation:

x = 53° + 45° { exterior angle of a triangle is equal to the sum of two opposite interior angles }

x = 98°

5 0
3 years ago
The price of a community pool membership has a one-time sign-up fee and a monthly fee. The price can be modeled by the function
Misha Larkins [42]
Your answer is option 1.
8 0
3 years ago
Sin5A/SinA-cos5A/cosA=4cos2A​
irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

\frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ LHS = \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}   \\  \\  =  \frac{ \sin5A \:\cos A -  \cos5A \:  \sin A}{\sin A \:\cos A }  \\  \\  =  \frac{ \sin(5A -A )}{\sin A \:\cos A}  \\  \\ =  \frac{ \sin 4A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =4\cos 2A \\  \\  = RHS \\  \\ thus \\  \\  \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ hence \: proved

5 0
3 years ago
Find the sum of the following ap .1) 1/15, 1/12, 1/10,....,to 11 terms​
sertanlavr [38]

Answer:

33/20

Step-by-step explanation:

1/12 - 1/15 = 5/60 - 4/60 = 1/60

d = 1/60

a_n = a_1 + d(n - 1)

a_11 = 1/15 + (1/60)(11 - 1)

a_11 = 1/15 + 1/6

a_11 = 4/60 + 10/60

a_11 = 14/60

a_11 = 7/30

a_12 = 14/60 + 1/60

a_12 = 15/60

a_12 = 1/4

s_n = n(a_1 + a_n)/2

s_11 = 11(1/15 + 7/30)/2

s_11 = 11(2/30 + 7/30)/2

s_11 = 11(9/30)/2

s_11 = 99/60

s_11 = 33/20

8 0
3 years ago
PLEASE HELP
kifflom [539]

\\ \sf\longmapsto \dfrac{x^2-1}{x^2+5x+4}\leqslant 0

  • Solving denominator

\\ \sf\longmapsto x^2+5x+4>0

\\ \sf\longmapsto x^2+4x+x+4>0

\\ \sf\longmapsto x(x+4)+1(x+4)>0

\\ \sf\longmapsto (x+4)(x+1)>0

\\ \sf\longmapsto x>-4\:or x>-1

  • Hence x\neq-1
  • x can't be 0 as it makes function undefined

\\ \sf\longmapsto -4

5 0
3 years ago
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