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3 years ago

5

jenna eats dinner at a restaurant. her bill is 14.50. jenna pays her bill and leaves a tip. write an inequality to represent the

total cost of jenna's dinner

1 answer:

Alex17521 [72]3 years ago

4 0

I'm thinking
y (greater than or equal to symbol) 14.50

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Write equivalent fractions for 1/3 and 1/4 using 12<br> as the common denominator

oee [108]

Answer:

1/3 = 4/12

1/4 = 3/12

Step-by-step explanation:

1/3 * 4/4 = 4/12

1/3 = 4/12

1/4 * 3/3 = 3/12

1/4 = 3/12

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3 years ago

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When v=5 and m=-4, evaluate: 4v2-m2

lions [1.4K]

Answer:

84

Step-by-step explanation:

4v^2 - m^2

let v=5 and m=-4

4 * (5)^2 - (-4)^2

4* (25) - (16)

100 - 16

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3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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4 years ago

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He is 30th place behind white tail deer, warthog, grizzly bear, and house cat

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3 years ago

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I need help! this is missing

mr Goodwill [35]

Answer:

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Step-by-step explanation:

if you solve an equation for a triangle using this method you'll get this result

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2 years ago

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