Question

What are the two roots of the quadratic equation? y=x squared-3x-4

Answer 1

Answer:

{x | x ∈ R, 4,-1}

Step-by-step explanation:

$y=x^2-3x-4$

$y=x^2+x-4x-4$

$y=(x^2+x)+(-4x-4)$

$y=x(x+1)+(-4)(x+1)$ Distributive property

$y=(x+(-4))(x+1)$ Distributive Property

$y=(x-4)(x+1)$

set y to 0

$0=(x-4)(x+1)$

set the factors to 0

$0=x-4; 0=x+1$

$4=x; -1=x$