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3 years ago

HELP ME ASAP PLZ !!!!!!!

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

5 0

Answer: C. 5.0 * 10^6

Step-by-step explanation:

1.6(10^14)

3.2(10^7)

(1.6)(100000000000000)

3.2(10^7)

160000000000000

3.2(10^7)

160000000000000

(3.2)(10000000)

160000000000000

32000000

=5000000 =

5*10^6

drek231 [11]3 years ago

4 0

Answer:

0.5 × 10^7

Step-by-step explanation:

1.6 divided by 3.2 =0.5

10 to the power or 14 minus 10 to the power of 7 = 10 to the power of 7

in division you must subtract the power number

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Evaluate p2 - r2 for p = 10, r = -4 and t = 5.

AlexFokin [52]

Answer:

Step-by-step explanation:

p^2-r^2= 10^2-(-4)^2

100-16=84

4 0

3 years ago

4. Prove by mathematical induction that n² +n < 2" whenever n is an integer greater than 4.

harkovskaia [24]

Step-by-step explanation:

n² + n < 2^n

so, let's see what happens, when I increase n by 1

(n+1)² + n + 1 < 2^(n+1) = 2×2^n

n² + 2n + 1 + n + 1 < 2×2^n

n² + 3n + 2 < 2×2^n = 2^n + 2^n

so, we added on the left and on the right side of the inequality sign compared to the original relation :

2n + 2 vs. 2^n

so, once the original relation becomes true (and we see by trying that for n = 1, 2, 3 and 4 it is not, but for n = 5 it becomes true), the next integer follows the original inequality plus the expressions mentioned above.

n² + n + (2n + 2) < 2^n + (2^n)

this inequality will remain true, if

2n + 2 <= 2^n

n + 1 <= 2^(n-1), which is true for n > 2 (and therefore also n > 4), because the "power of" function 2^n progresses much faster than a simple n+1

and therefore this relation remains true for any larger n.

5 0

3 years ago

Determine which statements are true about the extrema of the graphed fourth degree polynomial. Select all that apply.

dusya [7]

C and D are the answers

7 0

3 years ago

Read 2 more answers

If 25% of the students in your class like baseball, how

DaniilM [7]

Step-by-step explanation:

$\frac{8}{ \times } \times 100 = 25$

800/25=x

x=32 students

6 0

3 years ago

Suppose you form 5-letter strings from the letters C,O,M,P,U,T,I,N, and G.

Usimov [2.4K]

Answer:

9/4

Step-by-step explanation:

Base on the given info we first have to use:

∴ Permutation formula ∴

$\mathrm{_np_r=\frac{n!}{(n-r)!}}$

P = permutation

n = total number of objects

r = number of objects selected

Note that:
Order of which the letters are chosen is important.

Permutation Formula is which possible permutations of x elements from a set of n elements is given by.

From the given it states that five letters will be chosen from a set of nine.

Thus, now we have:

$N=P_(_9_,_5_)=\frac{9!}{(9-5)!}=\frac{9!}{4!}$

Thus, the answer is 9/4

Kavinsky

6 0

2 years ago