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Ipatiy [6.2K]
3 years ago
12

HELP IM SO SORRY IJAGEHQKSHAQHGSVWHSBWBSNSJWBSBEJEJEJEJJEEJ JUST HELP. JUST HELP ME OGMFBSBSBGSGSBSBANSJSJSJS NUMBERS 13 and 14!

?!!,!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0
14.The answer is 10 Celsius
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Nora's paper airplane flew 9 1/6 feet. That was 2 3/4 feet farther than Max's plane flew. Write and solve an equation to show ho
stepan [7]

Answer:

Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

i.e.

9\frac{1}{6}=\frac{55}{6}

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

2\frac{3}{4}=\frac{11}{4}

Thus the equation to show how far Max's paper airplane flew is:

\:\:9\frac{1}{6}-2\frac{3}{4}

=\frac{55}{6}-\frac{11}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

=\frac{110}{12}-\frac{33}{12}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{110-33}{12}

\mathrm{Subtract\:the\:numbers:}\:110-33=77

=\frac{77}{12}

=6\frac{5}{12}

Therefore, Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

6 0
3 years ago
Evaluate the expression when x=14 and y=12.
mina [271]

Answer:   348

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Help pls, it's more urgent than your wants to end your live
Ugo [173]

Answer:

just measure and then divide bro

Step-by-step explanation:

6 0
3 years ago
The first one is brainlyist
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Answer:

Step-by-step explanation:

6 0
2 years ago
In a college student poll, it is of interest to estimate the proportion p of students in favor of changing from a quarter-system
Contact [7]

Answer:

n=206

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.09, we can use as prior estimate of p 0.5, since we don't have any other info provided, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.09}{2.58})^2}=205.44  

And rounded up we have that n=206

3 0
3 years ago
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