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Scrat [10]
3 years ago
11

Using the equation ŷ = 5.4 + 1.7x, what is the predicted value if x is 1.2?

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Answer:

Using the equation ŷ = 5.4 + 1.7x, we can say that if x is 1.2, the predicted value will be 7.44.

Step-by-step explanation:

y=5.4+1.7(1.2)

Multiply 1.7 and 1.2 to get 2.04.

y=5.4+2.04

Add 5.4 and 2.04 to get 7.44.

y=7.44

There you go!

(Sources cited from Microsoft Math Solver.)

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An actor invested some money at 9% simple interest, and $42,000 more than three times the amount at 12%. The to
S_A_V [24]
<span>An actor invested some money at 9% simple interest, and $42,000 more than three times the amount at 12% per annum. </span><span>What we are after is amounts of interest invested at 9% and at 12%. Let's call them x and y respectively.

x=42000 at 9% = </span>$3,780.00 = $45,780.00
y=3x42000 at 12% = $15,120.00 = $141,120.00
x+y=$186,900.00
3 0
4 years ago
Which graph represents a system of equations with infinite solutions?<br> t<br> None of the above
Katena32 [7]

Answer:

the first one

Step-by-step explanation:

the two lines are on top of each other. The second one is not it because where they meet is at 1 point so there is one solution. The third one can't be it either because the two lines never cross each other so the last one has no solution.

3 0
3 years ago
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uranmaximum [27]

Answer: 10,000

Step-by-step explanation:

5 0
3 years ago
The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit
forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|

(a)Mean

Expected Value, \mu =\sum x_iP(x_i)

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076

Standard Deviation =\sqrt{\sum (x-\mu)^2P(x)}

=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0
3 years ago
A cheetah ran 75 meters at a speed of 25 meters per second. How long was the cheetah running?
Jobisdone [24]

Answer:

3 seconds

Step-by-step explanation:

SO if it ran 75 meters at a speed of 25 meters per second then you have to divide how many meters it ran by how many meters it took per second to find out how long the cheetah was running

75÷25=3

3 IS THE ANSWER

8 0
3 years ago
Read 2 more answers
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