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notsponge [240]
2 years ago
6

???????????????????????????????????????????????????????????????????????????????????????????????????????????????/

Mathematics
1 answer:
uranmaximum [27]2 years ago
5 0

Answer: 10,000

Step-by-step explanation:

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It costs $2.80 to make a sandwich at the local deli shop. To make a profit, the deli sells it at a price that is 170% of the cos
Natali [406]
I think the sandwich should sell for $7.56. 
5 0
3 years ago
Read 2 more answers
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
PLEASE HELP!!! In the diagram, line AB is a perpendicular bisector of segment CD. What is the length of CD?
ra1l [238]

Answer:

12

Step-by-step explanation:

AD is 6. a bisector splits a line in half. X would equal 6 meaning AD would equal 12.

6 0
2 years ago
Rita earns $10 per hour. She puts 5% of her earnings in savings. Write inequality to find how many hours Rita must work to save
Rina8888 [55]

Answer:

Rita must work 50 days  to save at least $25.

Step-by-step explanation:

The amount Rita earns per hour  = $10

The saving percentage =  5%

So, the savings of Rita per hour =  5% of $10

⇒5% of $10  = \frac{5}{100}  \times 10  = 0.5

or Rita saves $0.5 per hour.

The amount she wants to save at minimum  = $25

So, let she works at the minimum of k Days.

⇒\textrm{The number of hours she has to work}  = \frac{\textrm{Amount she needs saving}}{\textrm{Amount saved in 1 hour}}

or, k = \frac{25}{0.5}  = 50

The number of hours she has to work  =  50 days

Hence,  Rita must work 50 days  to save at least $25.

3 0
3 years ago
While preparing for a party a party planner began with 75 pieces of candy she ate 5 pieces while she was working then she put eq
Sloan [31]

The easiest way to find this answer is to work through it step by step.


She starts with 75 pieces.

She eats 5 pieces, so the # of pieces goes down from 75 to 75-5 = 70.

So she has 70 pieces left to put in the bags.

She puts the same amount in each of 10 bags... so we divide 70 by 10 to find the # of pieces in each bag.


70 divided by 10 is 7.


She put 7 pieces in each bag.

4 0
3 years ago
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