Answer:
x = 0, y = 7
Step-by-step explanation:
Solving a system of equations using substitution requires one side to be equal to a variable present in the equation, in this case x or y. We should simplify the equation using elimination before substituting to reduce the chance of error.
In order to use the elimination method, you have to create variables that have the same coefficient—then you can eliminate them. These equations arew already aligned for us.
3x - 10y=-70
-<u> 4x +9y = 63</u>
-x + y = 7
Now, for substitution, the equation must be set to a variable.
-x + y = 7
y = x + 7
Next, plug the equation in where applicable in another equation.
4x +9(x + 7) = 63
4x + 9x + 63 = 63
13x = 0
x = 0
The final step of substitution is to plug the known variable into an equation to find the other variable.
3(0) - 10y=-70
0 - 10y = -70
10y = 70
y = 7
I guarantee you this answer is correct, I worked it out using other methods and graphing prior to submitting this answer.
An acute angle is an angle less than 90 degrees. (smaller angle)
A right angle is exactly 90 degrees. (right angle)
An obtuse angle is over 90 degrees. (larger angle)
A reflex angle is any angle of 180 degrees. (largest angle)
You wouldn't *really* need a protractor to complete your homework; you could guesstimate.
I hope this helps!
Answer:
<u>The track consumes ≅ 61 liters of fuel every 100 kilometres</u>
Step-by-step explanation:
As we can see in the graph, the total distance that the truck can travel with 500 liters of fuel is ≅ 825 kilometres.
For answering the question properly, we use the Rule of Three Simple, this way:
Kilometres Liters of fuel
825 500
100 x
Solving for x, we have:
825 * x = 500 * 100
825x = 50,000
x = 50,000/825
x = 60.6 liters of fuel (61 rounding to the next whole)
x ≅ 61 liters of fuel
<u>The track consumes ≅ 61 liters of fuel every 100 kilometres</u>
Answer:
In M/n(x) x cannot be 0
Step-by-step explanation:
If any number is divided by 0, then that number is undefined and has no answer, so in math this is always avoided by not dividing with 0.
