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butalik [34]
3 years ago
5

Find the value of x

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

10 i think

Step-by-step explanation:

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Question in pic. please help!
ArbitrLikvidat [17]

Answer:

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

Step-by-step explanation:

We need to place the sides of triangle DE, DF and EF from longest to shortest.

The triangle has longest side that is opposite to the largest angle

We know two angles < E= 61° , <F= 59° we need to find <D

Sum of angles of triangle = 180°

So, 61°+59°+<D=180°

120°+<D=180°

<D=180°-120°

<D=60°

So, the largest angle is <E= 61°

The longest side must be opposite to <E so, the side is DF

The second largest angle is <D=60° so, second side will be EF

The smallest angle is <F=59° so, third (shortest) side will be DE

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

7 0
2 years ago
A pipe is leaking at 1.5 cups per day. How many gallons per week is the pipe leaking?
neonofarm [45]
1.5 cups per day...7 days per week....1.5 * 7 = 10.5 cups per week
16 cups = 1 gallon

16/1 = 10.5/x....16 cups to 1 gal = 10.5 cups to x gal
cross multiply
(16)(x) = (1)(10.5)
16x = 10.5
x = 10.5/16
x = 0.65625 rounds to 0.66 gallons per week
4 0
3 years ago
A map has a scale of 2 centimeters = 4 miles. Mary's drive to work is represented on the map as traveling 1cm north then 2.5 cm
mixas84 [53]

Answer:

Number of miles traveled by Mary to work = 7 miles

Step-by-step explanation:

total distance traveled on the Map by Mary = 1 + 2.5 = 3.5 cm

Scale of the map = 2 cm = 4 miles

Hence 3.5 cm = (3.5 x 4) ÷ 2 = 7 miles

8 0
3 years ago
Read 2 more answers
David flips a coin and rolls a standard number cube. Find the probability that the coin will show heads and the cube will show a
wariber [46]
There is a 1 chance of that happening
—
12
7 0
3 years ago
Solve the initial value problem y′+y=f(t),y(0)=0 where f(t)={1,−1, if t&lt;4 if t≥4 Use h(t−a) for the Heaviside function shifte
Anton [14]

Looks like the function on the right hand side is

f(t)=\begin{cases}1&\text{for }t

We can write it in terms of the Heaviside function,

h(t-a)=\begin{cases}1&\text{for }t\ge a\\0&\text{for }t>a\end{cases}

as

f(t)=h(t)-2h(t-4)

Now for the ODE: take the Laplace transform of both sides:

y'(t)+y(t)=f(t)

\implies s Y(s)-y(0)+Y(s)=\dfrac{1-2e^{-4s}}s

Solve for <em>Y</em>(<em>s</em>), then take the inverse transform to solve for <em>y</em>(<em>t</em>):

(s+1)Y(s)=\dfrac{1-e^{-4s}}s

Y(s)=\dfrac{1-e^{-4s}}{s(s+1)}

Y(s)=(1-e^{-4s})\left(\dfrac1s-\dfrac1{s+1}\right)

Y(s)=\dfrac1s-\dfrac{e^{-4s}}s-\dfrac1{s+1}+\dfrac{e^{-4s}}{s+1}

\implies y(t)=1-h(t-4)-e^{-t}+e^{-(t-4)}h(t-4)

\boxed{y(t)=1-e^{-t}-h(t-4)(1-e^{-(t-4)})}

4 0
2 years ago
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