The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
Answer:
True
Step-by-step explanation:
because the standard deviation describes how far, on average, each observation is from the typical value. a bigger variance means observations are more distant from the typical value, and therefore, more dispersed
Answer:
0.024
Step-by-step explanation:
Given,
Red marbles = 4,
Green marbles = 7,
Total marbles = 4 +7 = 11,
Ways of choosing 3 marbles =
Ways of choosing 3 red marble = 
Hence, the probability of 3 red marble = 


≈ 0.024
Answer:
1+1=2
Step-by-step explanation:
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