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aivan3 [116]
3 years ago
13

I FREAKING NEED HELPPP!!!

Mathematics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

\boxed{\begin{bmatrix}  3 &  - 1 \\  - 3 & 4\end{bmatrix}  = 12 - 3 =  \boxed{9} }\\ \\  \boxed{\begin{bmatrix}   -12 &  - 1 \\  12 &  5\end{bmatrix}  =  - 60-  ( - 12) =  \boxed{ - 48}} \\  \\ \boxed{\begin{bmatrix}  0&  - 1 \\  17 & 4\end{bmatrix}  = 0 -( - 17 )=  \boxed{17}} \\  \\\boxed{ \begin{bmatrix}  8&  - 1 \\  -  4 &  - 1\end{bmatrix}  =  - 8 - 4 =  \boxed{ - 12} }\\  \\ \boxed{\begin{bmatrix}  2 &  - 1 \\  2 &  - 1\end{bmatrix}  =  - 2 - ( - 2) =  \boxed{0}} \\  \\ \boxed{ \begin{bmatrix}  1 &  0\\  0 &1\end{bmatrix}  = 1 - 0 =  \boxed{1}}

Step-by-step explanation:

the \: determinant \: of  \: a \: matrix : A  \to\\If  \: A  =\begin{bmatrix}  x & y \\ a & b \end{bmatrix} \: then : \\  its \: determinant \: is \: givn \: by \to \\  |A|  =  (b \times x) - (a \times y) \\  \boxed{|A|  = bx - ax}

♨Rage♨

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6(4x+2)=3(8x+4) ??<br> please help asap
nasty-shy [4]
6(4x + 2) = 3(8x + 4)

Reorder the terms:
6(2 + 4x) = 3(8x + 4)
(2 * 6 + 4x * 6) = 3(8x + 4)
(12 + 24x) = 3(8x + 4)

Reorder the terms:
12 + 24x = 3(4 + 8x)
12 + 24x = (4 * 3 + 8x * 3)
12 + 24x = (12 + 24x)

Add '-12' to each side of the equation.
12 + -12 + 24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
0 + 24x = 12 + -12 + 24x
24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
24x = 0 + 24x
24x = 24x

Add '-24x' to each side of the equation.
24x + -24x = 24x + -24x

Combine like terms: 24x + -24x = 0
0 = 24x + -24x

Combine like terms: 24x + -24x = 0
0 = 0

Solving
0 = 0
4 0
3 years ago
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10/8c - 4/8 = 6/8 + 5/8c​
siniylev [52]

Answer: c = 2

Step-by-step explanation: Solve for c by simplifying both sides of the equation, then isolating the variable.

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a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b
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No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
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romanna [79]
<h3>1 Answer: Choice D) SAS</h3>

=================================================

Explanation:

LA stands for Leg Angle. More specifically, the angle is an acute angle. This theorem only works for right triangles. We see that ED = LK which is one pair of congruent leg segments. So that takes care of the L part of LA. However, we don't know anything about the acute angles. We don't know if angle E = angle L, or if angle F = angle M, or something along those lines. We need angle markers to tell us or not.

In short, we only have half the info needed for LA, so we must cross choice A off the list.

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HA stands for hypotenuse angle, or hypotenuse acute angle, and this rule only applies for right triangles. We don't know anything about the hypotenuse lengths if they are the same or not.

Similar to choice A, we don't know anything about the acute angles either.

Those two facts mean we must cross off choice B.

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AAS stands for Angle Angle Side. The order is important because the side is not between the angles. The diagram only shows one pair of angles that are congruent to one another. That pair being the 90 degree angles indicated with the square marker. We don't have another pair of angles, so we cannot use AAS.

Cross choice C off the list.

-----------------

We can use SAS because we have two pairs of congruent sides and one pair of congruent angles.

The congruent sides are

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That takes care of the two "S"s of "SAS". The "A" would be those two right angles which are congruent to one another. The angles are between the congruent sides which is important. Recall that SSA is not a valid congruence theorem.

So that's why choice D is the only answer.

-----------------

Side note: We could use the LL theorem, where L stands for leg, since we are given two pairs of congruent legs for each triangle. Like LA and HA, this only applies to right triangles. LL is a special case of SAS. However, LL isn't listed so we'll just be sticking with SAS as the only answer.

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Answer:

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