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Vera_Pavlovna [14]
3 years ago
11

A squash ball is thrown from the top of a building and falls to the ground below. The height of the ball above the ground is app

roximated by the relation h=-6t^2+24t + 30, where h is the height above the ground in metres and t is the elapsed time in seconds. Determine the maximum height that is reached by the ball. Show all your work. ​
Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

Step-by-step explanation:

the answer is 6 ft and all my workings are in the image above

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Step-by-step explanation:

You said the other one would be the last haha just kidding I'm glad to help.

16. \frac{k}{2}=(-5)^2

First, get rid of that parenthesis.

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Now multiply both sides by 2 so that you can isolate k

2(\frac{k}{2})=25*2

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19. \frac{r}{3}=\frac{121}{11}

This is a pretty easy one. If you didn't know, 121/11 is actually 11 :)

\frac{r}{3}=11

Simply multiply by 3 to isolate r :)

3(\frac{r}{3})=11*3

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The answer is (20,0). We can determine the  sum of two vector points by adding x1 to x2 and y1 to y2. This is like adding integers, the only difference is the answer is in vector form. In here, we have (x,y). x = 7+13 and y = 5+(-5). that is why we have the (20,0) as the answer.
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6 + 3(x+4)<br><br> PLEASEEE I NEED HELP
Ksivusya [100]

i'm going to assume you're supposed to solve for x

Answer:

x = -2

Step-by-step explanation:

so you're trying to get x out of the equation and by it self

i would start this off by setting the equation equal to 0

then subtract 6

i would then divide by 3 on each side

you should then have x+4=2

you then subtract 4 to cancel it out

you then get your answer of x = -2

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