The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean,
= 90 wpm
The standard deviation of the population ,
= 10
Sample size, n = 12
Sample mean,
= 95
The reading rate of students follows the normal distribution.
Let z = 
= 
= 1.732
Probability that the mean reading exceeds 95 wpm = P(
>95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
Learn more about Normal Distribution at brainly.com/question/27701525
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Answer:
t= 16.5
Step-by-step explanation:
See the steps below:)
It will take about 2 hours and 15 minuets
Hope this helped!
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I think the greatest possible starting number would be 1,214,449. If it was any higher, like 1,214,450, then the number would round up to 1,214,500, and you don't want that.
Hopefully this helps! Let me know if you have any more questions.