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ozzi
3 years ago
14

A potteruses clayat a daily rate that is normally distributed with a mean of 27pounds and a standard deviation of 8pounds. When

the potterplaces an order for the clayit requires 5days for the order to arrive.7.What is the Service Level if the shop places an order when inventory reaches 155pounds
Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

100 percent

Step-by-step explanation:

mean ( average daily demand ) ( d )  = 27 pounds

standard deviation of demand ( std ) = 8 pounds

Lead time ( taken order takes to arrive ) ( L ) = 5 days

Reorder point = 155 pounds

<u>Determine the service level ) </u>

Applying the equation below

Reorder point = d x L + (Z x  std )       note : Z = service factor

155 = 27 * 5 + ( Z  * 8 )

155  = 135 + 8Z

hence Z ( service factor ) = ( 155 - 135 ) / 8 = 2.5

hence the service level is ≈ 100 percent

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A parking garage charges 21.00 for 6 hours how much does it charge per hour
alexdok [17]

Answer:

If a parking garage charges $21 for 6 hours in order to find out how much it charges per hour you will need to divide 21 by 6:

21÷6=3.50

So in conclusion a parking garage charges

$3.50/hour

5 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
Factoring trinomials
Tcecarenko [31]

c^22c^2 + 13c +21 \\4c^2 + 13(2)c + 42\\(2c + 6)(2c+7)\\(c+3)(2c+7)


This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying  c^2. This is the second line. Then, you could take the square of the 4c^2, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have (2c + 6) (2c +7)

The last step is divide by the number that we multipy in the first step.

4 0
3 years ago
A rectangle is twice as long as it is wide. If its length and width are both
puteri [66]

Answer:

a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle

Step-by-step explanation:

Let l = the original length of the original rectangle

Let w = the original width of the original rectangle

From the description of the problem, we can construct the following two equations

l=2*w (Equation #1)

(l+4)*(w+4)=l*w+88 (Equation #2)

Substitute equation #1 into equation #2

(2w+4)*(w+4)=(2w*w)+88

2w^2+4w+8w+16=2w^2+88

collect like terms on the same side of the equation

2w^2+2w^2 +12w+16-88=0

4w^2+12w-72=0

Since 4 is afactor of each term, divide both sides of the equation by 4

w^2+3w-18=0

The quadratic equation can be factored into (w+6)*(w-3)=0

Therefore w=-6 or w=3

w=-6 can be rejected because the length of a rectangle can't be negative so

w=3 and from equation #1 l=2*w=2*3=6

I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.

5 0
3 years ago
Please help on one math question
kipiarov [429]

Hello from MrBillDoesMath!

Answer:

225

Discussion:

Sum ( 2n - 1)                  from  n = 1 to 15              

= Sum(2n) - Sum(1)        from n = 1 to 15

= 2 Sum(n) - Sum(1)       from n = 1 to 15

= 2* 15(15+1)/2  - (1 + 1 + .. + 1)

The first value comes from the fact that the sum of the first n integers is  n(n+1)/2. The latter value sums 15 1's.

= 2 * 15 * 16/2 - 15                    => 2/2 = 1

= 15*16 - 15                               => 15*16 = 240

= 240 - 15

= 225

Thank you,

MrB

6 0
3 years ago
Read 2 more answers
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