Picture attached below A. 1/3 B. 5/13 C. 4/5 D. 12/13
1 answer:
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Answer:
f(x) is continuous on the interval [0, 1], f(0) = <u>-2</u> , and f(1) = <u>1.718</u> . Since f(0) < 0 < f(1) , there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation ex = 3 − 2x, in the interval (0, 1)
Step-by-step explanation:
From the question we are told that
The equation is
The interval is [0, 1]
Generally f(0) is
=>
=>
Generally f(1) is
From the value we see that at x = 0 , f(0) = -2 which is below the x-axis
and the at x = 1 , f(1) = 1.718 which is above the x-axis
Now the according to Intermediate Value Theorem , given the condition stated above, there will exist a root c in the interval such that
f(c) = 0