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NISA [10]
3 years ago
10

Picture attached below A. 1/3 B. 5/13 C. 4/5 D. 12/13

Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

B. 5/13

Step-by-step explanation:

What I used:

|hypotenuse|^2 = |opposite|^2 + |adjacent|^2 (right angle triangle)

sin x = opposite / hypotenuse

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Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)
poizon [28]

(x+2)^{2}+(y-5)^{2}= 34

The equation of a circle in standard form is

(x-a)^{2}+(y-b)^{2}=r^{2}

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [\frac{1}{2}(xx_{1}+x_{2}, \frac{1}{2}(y_{1}+y_{2}

where (x_{1},y_{1}=(3,8) and (x_{2},y_{2}=(-7,2)

centre = (\frac{1}{2}(3-7),\frac{1}{2}(8+2)) = (-2,5)

Calculate r using the distance formula

r = √(x_{2}-x_{1})²+(y_{2}-y_{1})²)

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equation of circle is : (x+2)²+(y-5)² = 34


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3 years ago
PLEASE HELP ME!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!
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b

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