All categories

3 years ago

Help me please,Thanks

Mathematics

1 answer:

alisha [4.7K]3 years ago

8 0

Answer: The width is: " 10 in. " .
________________________________________________
Explanation:
________________________________________________
Consider a "rectangular prism".
________________________________________________
The formula for the Volume of a rectangular prism:
________________________________________________

V = L * w * h ;
_________________________________________________
in which:

V = volume = 120 in.³ ;
L = length = 8 in.
w = width = ??
h = height = 1.5 in.
____________________________________________
We want to solve for "w" (width) ;
____________________________________________
Given the formula:
____________________________________________

V = L * w * h ;
____________________________________________
Rewrite the formula; by dividing EACH SIDE of the equation by
"(L * h)" ; to isolate "w" on one side of the equation;
and to solve for "w" ;
_____________________________________________
→ V / (L * h) = ( L * w * h) / (L * h) ;

to get:
_________________________________
→ V / (L * h) = w ;

↔ w = V / (L * h) ;
_________________________________
Plug in our given values for "V", "L"; and "h"; to solve for "w" ;
____________________________________________________
→ w = (120 in.³) / (8 in. * 1.5 in.) ;

→ w = (120 in.³) / (12 in.²) ;

→ w = (120/12) in. = 10 in.
____________________________________________________

You might be interested in

Simplify the following expression:

Morgarella [4.7K]

Answer:

2nd option

Step-by-step explanation:

Given

2x - 8y + 3x² + 7y - 12x ← collect like terms

= 3x² + (2x - 12x) + (- 8y + 7y)

= 3x² + (- 10x) + (- y)

= 3x² - 10x - y

8 0

2 years ago

Solve for w. 5w + 9z = 2z + 3w

DIA [1.3K]

When solving for a variable, you get the variable you're trying to solve for on one side and everything to the opposite of that variable.

We have the equation 5w + 9z = 2z + 3w.

Usually the variable we're solving for we want on the left. But it's fine to have it on the right side, too.

Let's subtract 9z from the left-hand side. That way, the 5w will be alone on the left-hand side.

And remember, anything we do on one side we do to the other side.

5w + 9z - 9z = 2z + 3w - 9z
5w = -7z + 3w

The 3w term on the right-hand side needs to be removed. So, subtract each side by 3w.

5w - 3w = -7z + 3w - 3w
2w = -7z

Now, we need to divide each side by 2 to see what the w variable is equal to.

2w / 2 = -7z / 2
w = -7z / 2 or w = -3.5z

So, w is equal to -3.5z.

7 0

3 years ago

Read 2 more answers

If x^2=20 what is the value of x

tankabanditka [31]

Answer:

Step-by-step explanation:

x^2=20

just square both sides and u get

x = 4.472135955

6 0

3 years ago

Read 2 more answers

What are the steps to converting 720 seconds into hours?

Nataly [62]

This conversion of 720 seconds to hours has been calculated by multiplying 720 seconds by 0.0002 and the result is 0.2 hours.

3 0

3 years ago

Read 2 more answers

Let y(t) be the solution to y˙=3te−y satisfying y(0)=3 . (a) Use Euler's Method with time step h=0.2 to approximate y(0.2),y(0.4

OLEGan [10]

Answer:

$y(0.2)=3$ , $y(0.4)=3.005974448$ , $y(0.6)=3.017852169$ , $y(0.8)=3.035458382$ , and $y(1.0)=3.058523645$

The general solution is $y=\ln \left(\frac{3t^2}{2}+e^3\right)$

The error in the approximations to y(0.2), y(0.6), and y(1):

$|y(0.2)-y_{1}|=0.002982771$

$|y(0.6)-y_{3}|=0.008677796$

$|y(1)-y_{5}|=0.013499859$

Step-by-step explanation:

Point a:

The Euler's method states that:

$y_{n+1}=y_n+h \cdot f \left(t_n, y_n \right)$ where $t_{n+1}=t_n + h$

We have that $h=0.2$ , $t_{0}=0$ , $y_{0} =3$ , $f(t,y)=3te^{-y}$

We need to find $y(0.2)$ for $y'=3te^{-y}$ , when $y(0)=3$ , $h=0.2$ using the Euler's method.

So you need to:

$t_{1}=t_{0}+h=0+0.2=0.2$

$y\left(t_{1}\right)=y\left(0.2)=y_{1}=y_{0}+h \cdot f \left(t_{0}, y_{0} \right)=3+h \cdot f \left(0, 3 \right)=$

$=3 + 0.2 \cdot \left(0 \right)= 3$

$y(0.2)=3$

We need to find $y(0.4)$ for $y'=3te^{-y}$ , when $y(0)=3$ , $h=0.2$ using the Euler's method.

So you need to:

$t_{2}=t_{1}+h=0.2+0.2=0.4$

$y\left(t_{2}\right)=y\left(0.4)=y_{2}=y_{1}+h \cdot f \left(t_{1}, y_{1} \right)=3+h \cdot f \left(0.2, 3 \right)=$

$=3 + 0.2 \cdot \left(0.02987224102)= 3.005974448$

$y(0.4)=3.005974448$

The Euler's Method is detailed in the following table.

Point b:

To find the general solution of $y'=3te^{-y}$ you need to:

Rewrite in the form of a first order separable ODE:

$e^yy'\:=3t\\e^y\cdot \frac{dy}{dt} =3t\\e^y \:dy\:=3t\:dt$

Integrate each side:

$\int \:e^ydy=e^y+C$

$\int \:3t\:dt=\frac{3t^2}{2}+C$

$e^y+C=\frac{3t^2}{2}+C\\e^y=\frac{3t^2}{2}+C_{1}$

We know the initial condition y(0) = 3, we are going to use it to find the value of $C_{1}$

$e^3=\frac{3\left(0\right)^2}{2}+C_1\\C_1=e^3$

So we have:

$e^y=\frac{3t^2}{2}+e^3$

Solving for y we get:

$\ln \left(e^y\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y\ln \left(e\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y=\ln \left(\frac{3t^2}{2}+e^3\right)$