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3 years ago

Please help me with number 2 (15pts)

Mathematics

1 answer:

kipiarov [429]3 years ago

4 0

Answer:

this only iz 8 pts tho ;(

Step-by-step explanation:

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Circle x centered at the Oregon with radius 10

pantera1 [17]

Answer:

circumference = 2 * 22/7*10

440/7

Step-by-step explanation:

4 0

3 years ago

6. Matthew is planning to build a right triangular

saul85 [17]

The answer to this question will be B

8 0

3 years ago

K=am+3mx solve for m

Otrada [13]

Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)

7 0

3 years ago

Jillian and Dawn are playing a game of miniature golf. In this game, the score on a hole is the number of putts it takes to get

frozen [14]

Answer:

Step-by-step explanation:

Discussion

This should be answered with the mean. The lower the mean, the lower the score it took to get the mean. So B is the answer.

4 0

1 year ago

Expand the given power by using Pascal’s triangle. (9a - 10b)^6

xxMikexx [17]

Answer:

$531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

Step-by-step explanation:

1 n=0

1 1 n=1

1 2 1 n=2

1 3 3 1 n=3

1 4 6 4 1 n=4

1 5 10 10 5 1 n=5

1 6 15 20 15 6 1 n=6

This is where n is the exponent in

$(x+y)^n$ .

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

Now we want to expand:

$(9a-10b)^6$ or we we can rewrite as $(9a+(-10b))^6$ .

Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

$((9a)+(-10b))^6$

$=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6$

Let's simplify a bit:

$=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6$

$=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

8 0

3 years ago