So really all you have to do is simply the expressions on top to match them.
Starting with (4t-8/5)-(3-4/3t), distribute the negative sign to the right portion in parentheses, then distribute it all out and you will get 16/3t- 23/5
Basically, use distribution to simplify, here's all the matches:
(4t-8/5)-(3-4/3t) --> 16/3t- 23/5
5(2t+1)+(-7t+28) --> 3t+33
(-9/2t+3)+(7/4t+33) --> -11/4t+36
3(3t-4)-(2t+10) --> 7t-22
x^2-9x-6=0
Use the quadratic formula to get (9+sqrt(105))/2 or (9-sqrt(105))/2
100/5= 20
20 x 4 = 80
80 + 43 = 123
if my math is correct then none are correct
(prolly a typo)
To solve this problem, we make use of the formula of
combination.
nCr = n! / r! (n – r)!
where n is the total number of subject teachers and r is
the number of subjects r = 1
For the English class n = 3
3C1 = 3! / 1! (3 – 1)! = 3
For the Algebra class n = 4
4C1 = 4! / 1! (4 – 1)! = 4
For the Biology class n = 2
2C1 = 2! / 1! (2 – 1)! = 2
The total number of different schedules would be the
product of the three combinations:
total combinations possible = 3 * 4 * 2
total combinations possible = 24
Answer:
The answer to your question is: x₁ = 9 ; x₂ = -2, third option
Step-by-step explanation:
The excluded values are those that make the denominator equal to zero.
To find the excluded values, just factor the denominator and equal to zero to find the roots.
Process
x² - 7x - 18
- Find to numbers that added gives -7 and multiply -18.
- These numbers are -9 and + 2, because
-9 + 2 = -7
and -9 x 2 = -18
(x - 9) (x + 2) = 0
x₁ - 9 = 0 x₂ + 2 = 0
x₁ = 9 x₂ = -2
Test
(9)² - 7(9) - 18 (-2)² - 7(-2) - 18
81 - 63 - 18 4 + 14 - 18
81 - 81 18 - 18
0 0
