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Leni [432]
3 years ago
14

How many liters is 250,000 cm3?

Mathematics
2 answers:
Semmy [17]3 years ago
7 0
It's 250 because 1 liter 1000 and 250 multiply by 100 is 250 000.
eimsori [14]3 years ago
3 0
Once cubic centimeter = 1 milleter

1 mL = 1000 L

250,000 ÷ 1000 = 250

There are 250 liters in 250,000 cubic centimeters.
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Factor the numerator and denominator and then reduce the fraction:
Kazeer [188]

\boxed{\frac{2xy-3y}{x}}

<h2>Explanation:</h2>

Here we have the following expression:

\frac{16xyz-24zy}{8xz} \\ \\ \\ Prime \ factorization: \\ \\ 16=2^4 \\ \\ 24=2^3\cdot 3 \\ \\ 8=2^3

So we can rewrite this as follows:

\frac{2^4xyz-2^3\cdot 3zy}{2^3xz} \\ \\ \\ Common \ factor \ 2^3z \ in \ the \ numerator: \frac{2^3z(2xy-3y)}{2^3xz} \\ \\ \\ Commutative \ property \ in \ the \ denominator: \\ \\ \frac{2^3z(2xy-3y)}{2^3zx} \\ \\ \\ Simplyfing: \\ \\ \boxed{\frac{2xy-3y}{x}}

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

#LearnWithBrainly

5 0
4 years ago
The weights of cars passing over a bridge has a mean of 3550 lb and a standard deviation of 870 lb. Assume that the weights of t
elena-s [515]

Step-by-step explanation:

Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs.  So choose appropriate answer accordingly (near the end)

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870

Observed value, X = 3000

We calculate

Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Probability of weight below 3000 lbs

= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334

Answer:

Probability that a car randomly selected is less than 3000

= P(X<3000) = 0.2636 (to 4 decimals)

Probability that a car randomly selected is greater than 3000

= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)

5 0
3 years ago
Read 2 more answers
On a particular day, the wind added 5 miles per hour to Alfonso's rate when he was cycling with the wind and subtracted 5 miles
Nata [24]

now, this is pretty much the same as the one before it with Jaime, so I'll do this without much fuss.

recall d = rt.

a = Alfonso's rate

with the wind his speed is a + 5, against it is a - 5, 60 miles with it and 30 miles against it, all in the same time of t hours.

\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ &------&------&------\\ \textit{with the wind}&60&a+5&t\\ \textit{against the wind}&30&a-4&t \end{array} \\\\\\ \begin{cases} 60=(a+5)t\implies \frac{60}{a+5}=\boxed{t}\\\\ 30=(a-4)t\\ -------------\\ 30=(a-4)\left( \boxed{\frac{60}{a+5}} \right) \end{cases} \\\\\\ 30(a+5)=(a-4)60\implies 30a+150=60a-240 \\\\\\ 390=30a\implies \cfrac{390}{30}=a\implies 13=a

8 0
3 years ago
Any thoughts im really confused on it
alexdok [17]
Pedro did KCF (Keychain flip)
Step 1&2 are correct as he did the process right.
So, he must of multiplied or simplified wrong
So, 4×8= 32
And 7×8=56
As you may have noticed he has gotten 20/50 instead of 32/56

Where Pedro messed up is step 3

HOPE THIS HELPER (:!
7 0
3 years ago
Marcos reads 3, books in 1 3/4 weeks.
Fofino [41]

Answer:

x  = \frac{12}{7}\ books

Step-by-step explanation:

Given

3\ books = 1\frac{3}{4}\ weeks

Required

Number of books in 1 week

Represent the number of books in 1 week with x.

So, we have:

3\ books = 1\frac{3}{4}\ weeks

x = 1\ week

Cross Multiply

x * 1\frac{3}{4} = 3 * 1

x * 1\frac{3}{4} = 3

Convert fraction to improper fraction

x * \frac{7}{4} = 3

Multiply through by \frac{4}{7}

x * \frac{7}{4}*\frac{4}{7} = 3 * \frac{4}{7}

x  = 3 * \frac{4}{7}

x  = \frac{12}{7}\ books

<em>Hence: 12/7 books were read in a week</em>

7 0
3 years ago
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