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arlik [135]
3 years ago
8

Please help me!

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0

Answer:

± seventeen (17) or ± 5.67%.

Step-by-step explanation:

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The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is r
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Answer:

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

P(c \leq X \leq d) = \frac{d - c}{b - a}

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This means that a = 50, b = 52

If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

P(51.5 \leq X \leq 51.7) = \frac{51.7 - 51.5}{52 - 50} = \frac{0.2}{2} = 0.1

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

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(c)

Step-by-step explanation:

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