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3 years ago

11

Pls help I’ll brainlest ASAP

1 answer:

charle [14.2K]3 years ago

7 0

The answer is G=34 !!!!!!

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Frank is having the car pets in his house cleaned. The cost of the cleaning is calculated from the area of the carpets. C= the c

asambeis [7]

Answer:

Cost of the cleaning, C is the dependent variable

Area of the carpet, a is the independent variable

Step-by-step explanation:

cost of the cleaning is calculated from the area of the carpets

C= the cost of the cleaning a= the area of the carpets.

Cost of the cleaning, C is the dependent variable

Area of the carpet, a is the independent variable

A dependent variable is a variable which depends on other factors to exist. They take their values based on other factors. Their value is changed as a result of a change in independent variable

An independent variable is a variable which does not change as a result of the change in other factors. They take their values irrespective of external factors around them.

5 0

3 years ago

Jerneii writes the set of ordered pairs below. The set represents a function.

BlackZzzverrR [31]

Answer:

WOMP WOMP WOMP!!!

Step-by-step explanation:

4 0

3 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago

Find the area and perimeter.

DanielleElmas [232]

Step-by-step explanation:

Perimeter = 12 + x + 6 + 2x + 5

Perimeter = 3x + 23.

Area = ½ × b × h

Area = ½ × 12 × (x + 6)

Area = 6(x + 6)

Area = 6x + 36

4 0

3 years ago

Name the property the equation illustrates.

Maslowich

I think it is the associative property of Addition

6 0

3 years ago

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