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mel-nik [20]
3 years ago
11

Pls help I’ll brainlest ASAP

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0
The answer is G=34 !!!!!!
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5,3,-7,-8,-2 order from greatest to least
Burka [1]

Answer

-8, -7, -2, 3, 5

Explanation

Positive numbers go up as they increase.

Negative numbers go up as they decrease.

3 0
3 years ago
Of 5 Sarah, Fiona and David share £40 in a ratio 3:3:2. How much money does each person get?​
Olin [163]

Answer:

15

15

10

Step-by-step explanation:

3/8 x £40 = £15 for Sarah

3/8 x £40 = £15 for Fiona

2/8 x£40 = £10 for david

6 0
3 years ago
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Write the solution to the given inequality in interval notation.
Vikentia [17]

Answer:

The answer should be C.

7 0
3 years ago
QUESTION 4
ANEK [815]

(2x-1)(x+4)=0

Step-by-step explanation:

A random zero property of multiplication is taken to find the solution

(2x-1)(x+4)=0

consider a=2x-1 and b=x-4                                      a.b=0

                                                                           either a or b or both must be 0

equating both the equations

2x-1=0 or x=4=0        x-4=0

2x-1=0                         x=4  

2x=1

x=1/2

substitute the values of x in the main equation

[2(1/2)-1][(1/2)+4]=0

3 0
3 years ago
Read 2 more answers
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
Read 2 more answers
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