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3 years ago

One side of a triangle is 7 and another side is 10. Which of the values below could

Mathematics

2 answers:

Mariana [72]3 years ago

6 0

Answer:

Step-by-step explanation:

given 2 sides of a triangle, then the third side, x , is in the range

difference of 2 sides < x < sum of 2 sides , that is

10 - 7 < x < 10 + 7

3 < x < 17

The only values in the list between 3 and 17 are 4 and 16.

That is III and IV only → C

IrinaK [193]3 years ago

4 0

x is the third side of the triangle, we have:

7 + 10 > x > 10 - 7

<=> 3 < x < 17

so the answer is C. III and IV only

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Can some one please help meeee

adoni [48]

Answe:

Explanation:

36/3=12

Because in the question it’s written that it costs 3 time the shirt.

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3 years ago

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If 8.45% life of each mobile phone is used in a day by a typical user for which mobile phone is 2.1 hours of battery life used i

mamaluj [8]

8.45% = 0.0845

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3 years ago

Determine the time necessary for P dollars to double when it is invested at interest rate r compounded annually, monthly, daily,

kipiarov [429]

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Answer:

annually: 9.01 years
monthly: 8.69 years
daily: 8.67 years
continuously: 8.66 years

Step-by-step explanation:

For interest compounded in discrete intervals, the formula is ...

A = P(1 +r/n)^(nt)

We want to find t for P=1 and A=2, so we have ...

2 = (1 +r/n)^(nt)

ln(2) = nt·ln(1+r/n)

t = ln(2)/(n·ln(1+r/n))

A table of values for r=0.08 is attached.

For continuous compounding, the formula is ...

A = Pe^(rt)

t = ln(A/P)/r = ln(2)/0.08 ≈ 8.66434 . . . . years

annually: 9.01 years
monthly: 8.69 years
daily: 8.67 years
continuously: 8.66 years

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3 years ago

I need some math help

Kobotan [32]

This is an answer should help you

8 0

3 years ago

6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t

Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

$\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}$

Therefore, there 12 possible combinations from these

3 0

2 years ago