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Ivenika [448]
3 years ago
14

A formula can be rewritten to isolate a different _______.

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

Variables

Step-by-step explanation:

EDG2021

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Bob is building a wooden cabin. The cabin is 30 meters wide. He obtained a bunch of 17 meters long wooden beams for the roof of
qaws [65]
The roof will be in the shape of an isosceles triangle with a base length of 30 m and two sides that are 17 m. The two 17 m beams will have the same angle of elevation since they have to might in the middle.

So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.

cos(\theta) =  \frac{adjacent}{hypotenuse}

cos(\theta)= \frac{15}{17}

cos^{-1}( \frac{15}{17})=\theta

\theta = 28.1^{\circ}

The answer  is 28.1 degrees
3 0
3 years ago
Please help! All in the image:
charle [14.2K]

Answer:

66 cm^2

Step-by-step explanation:

By equating the area we get x = 6.

8 0
3 years ago
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What is the height of this isosceles triangle?
erastova [34]

Answer:

height ≈ 11.9 units

Step-by-step explanation:

Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.

Using the sine ratio in one of these right triangles, then

sin48° = \frac{opposite}{hypotenuse} ( the opposite is the height h )

sin48° = \frac{h}{16} ( multiply both sides by 16 )

16 × sin48° = h , thus

h ≈ 11.9 ( to the nearest tenth )

5 0
3 years ago
Help I forgot how to do this​
serg [7]

Answer:

(5,1)

Step-by-step explanation:

5 0
3 years ago
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Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[
kherson [118]

Answer:

Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = ( x₁ , x₂)   and  Vector  Y = (y₁ , y₂)

then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²

where, x₁ = 8, x₂ = -5   and  y₁ = -1 , y₂ = -9

Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85

4 0
3 years ago
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