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3 years ago

✨Could ✨someone✨help ✨me ✨with ✨this? ✨It ✨would ✨be ✨much ✨appreciated✨

Mathematics

2 answers:

Nataly_w [17]3 years ago

8 0

Answer:

Step-by-step explanation:

2x-5y=-25

5y=2x+25

y=2/5 x+5

Lorico [155]3 years ago

6 0

Answer:

B. y = 2/5x + 5

Step-by-step explanation:

You might be interested in

Solve the system of linear equations. Check your solution. y=2x-2 <br> y=2x+9

natulia [17]

2X-2=2X+9
Add 2

2X=2X+11
Subract 2X
0= 11

This has no solution to this problem

8 0

3 years ago

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is

$f(x)=\begin{cases}0&0\leq x$ .

To show that the convergence is not uniform consider $0$ . For any $n>1$ choose $x\in (0,1)$ such that $\varepsilon^{1/n}$ . Then

$\varepsilon$

This implies that the convergence is not uniform.

8 0

3 years ago

Same receive the weekly paycheck here's a copy of one of his pay statements if there are four pages per month what is Sam's mont

Lady_Fox [76]

$654.48 i believe. maybe

4 0

3 years ago

A physician assistant orders 500 mL of D5NS over 5 hours. How many milliliters per hour will the patient receive? (Round to the

lara31 [8.8K]

Answer:

100

Step-by-step explanation:

500ml÷5h=100ml/h

3 0

2 years ago

(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)

tia_tia [17]

Answer:

$(4x-9)^2*(2x^2+2x+1)^2$

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

] (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1 Multiply (4x-9) by (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (4x-9) and the exponents are :

1 , as (4x-9) is the same number as (4x-9)1

and 1 , as (4x-9) is the same number as (4x-9)1

The product is therefore, (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1 Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2 Multiply (2x2+2x+1) by (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (2x2+2x+1) and the exponents are :

1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

and 1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

The product is therefore, (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

(4x - 9)2 • (2x2 + 2x + 1)2

6 0

2 years ago