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slamgirl [31]
3 years ago
15

Lesson 4 Solving One Variable Equation

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

b = -³¹⁄₃

Step-by-step explanation:

We can solve this Algebra equation by separating the variable and constants.

3b + 15 = -26 - 20

3b + 15 = -46

3b = -31

b = -³¹⁄₃

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What is the image of (8,7) after a reflection over the line y=-x?
4vir4ik [10]

Answer:

(-7,-8)

Step-by-step explanation:

The original point is (8,7)

To reflect it, just switch their places and change their signs.

So, (-7,-8)

8 0
3 years ago
Pls help <br> No links pls and tyyyy!!!
bearhunter [10]

Answer:

Assuming ur looking for the circumference

its 24.94pi

(the last one)

Step-by-step explanation:

Brainliest would be eappreciated :)

4 0
2 years ago
How many solutions does the equation have? a+5=1/5(5a+25)
Iteru [2.4K]
A + 5 = \frac{1}{5} (5a + 25)

First, simplify \frac{1}{5} (5a + 25) to \frac{5a+25}{5} / Your problem should look like: a + 5 =  \frac{5a+25}{5}
Second, multiply both sides by 5. / Your problem should look like: 5a + 25 = 5(a + 5)
Third, expand to get rid of parenthesis. / Your problem should look like: 5a + 25 = 5a + 25
Fourth, both sides are equal, resulting it having infinite solutions.

Answer: infinite solutions

6 0
3 years ago
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
6 0
2 years ago
A circle with radius \pink{3}3start color #ff00af, 3, end color #ff00af has a sector with a central angle of \purple{\dfrac{1}{9
Molodets [167]

Answer:

\dfrac{3}{2}\pi = \green{A_s}  

2

3

​  

π=A  

s

​

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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