Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
C) y = -cos(x) +2
Step-by-step explanation:
The centerline is 2, so 2 is added. That leaves out choices A and B.
There is a minimum (not a maximum) at x=0, so the multiplier is negative, eliminating choice D.
The correct equation is that of C: y = -cos(x) +2.
20,000 x 25 = 500,000
500,000 divided by 100 = 5,000 members are lost.
Members left = 15,000
Members added = 10,000
Members every year = Members left + Members added
= 15,000 + 10,000
= 25,000
Watch closely. I'll try to go slow.
Stop me if I go too fast, or if I do anything that you don't understand.
Ready ?
You said d = r t
Divide each side by ' t ' : d / t = r
(17*3) --- to find the total points of the 3 quizzes
17*3=51
the third quiz grade=51-14-19=18
hope this helps
