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3 years ago

11

Two supporting reasons are missing from the proof. Complete the proof by dragging and dropping the appropriate reasons into each

of the empty boxes.
Given: m∥nm∠1=120°

Prove m∠6=60°

1 answer:

Sloan [31]3 years ago

4 0

Answer:

The first one would be corresponding angles postulate and the second one is linear pair postulate.

Step-by-step explanation:

You might be interested in

Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.

Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

the points will be clustered according to their distance to the centroids.
Then centroids are updated as the cluster means.
This process continues until clusters doesn't change anymore

1) <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = $(18-6)^{2}$ + $(18-12)^{2}$ + $(18-18)^{2}$ + $(18-24)^{2}$ + $(18-30)^{2}$ + $(45-42)^{2}$ + $(45-48)^{2}$ =378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12) mean:9

second cluster (18,24,30,42,48) mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

Sum of Squared errors = $(15-6)^{2}$ + $(15-12)^{2}$ + $(15-18)^{2}$ + $(15-24)^{2}$ + $(40-30)^{2}$ + $(40-42)^{2}$ + $(40-48)^{2}$ =348

6 0

4 years ago

Evaluate the expression - |7-9|

timama [110]

Answer: -2

Step-by-step explanation: As our first step, we simplify inside the absolute value. 7 - 9 is -2 so we have -|-2|.

A common mistake at this point in the problem is to change the minus a negative to plus a positive but don't fall into this trap.

We must ignore the negative outside the absolute value until our very last step in this problem.

So we take the absolute value of -2 which is 2 and we have -(2) or -2.

Notice that I used parentheses around the 2 as it comes out of the absolute value.

5 0

4 years ago

A bag contains 240 marbles that are either red, blue, or green. The ratio of red to blue to green marbles is 5:2:1. If one-third

Andrej [43]

The fraction of the remaining marbles in the bag will be blue is 6/17.

<h3>What fraction of the remaining marbles in the bag will be blue?</h3>

The first step is to determine the initial number of marbles in the bag:

Initial number of red marbles in the bag : (5/8) x 240 = 150

Initial number of blue marbles in the bag : (2/8) x 240 = 60

Initial number of green marbles in the bag : 240 - 150 - 60 = 30

Number of red marbles remaining after 1/3 is removed = (1 - 1/3) x 150

2/3 x 150 = 100

Number of green marbles remaining after 2/3 is removed = (1 - 2/3) x 30

1/3 x 30 = 10

Total number of marbles now in the bag : 100 + 10 + 60 = 170

Fraction of blue marbles = 60 / 170 = 6/17

To learn more about ratios, please check: brainly.com/question/9194979

#SPJ1

7 0

2 years ago

Someone plz help me I will give brainliest!!

Naily [24]

Answer

well sorry cant answer the other question see if it works on here

Step-by-step explanation:

4 0

3 years ago

What is the slope of the line that passes through (-2,-3) and (1,1)

kramer

Slope:
$m = \frac{y _{2} - y _{1}}{x_{2} - x _{1}}$

Slope is rise over run. It is a ratio of the amount of the y-axis over the amount of x-axis. So, now assign the first group of numbers, (-2,-3) as 1; then the second group, (1,1) as 2. Like this:
$first \: group(x _{1} ,y _{1}) \\ second \: group(x_{2},y_{2})$
Notice the subscripted numbers designate the group number. Next, plug in the numbers and do the math.
$\frac{1 - ( - 3)}{1 - ( - 2)} = \frac{1 + 3}{1 + 2} = \frac{4}{3}$
So, the slope, m, is equal to four thirds.

m = 4/3

6 0

3 years ago