Answer:
18 days
Step-by-step explanation:
It depends on the number of frogs, but if there is one frog then it would be...
9÷.5= 18 (18 half cups in 9 cups)
Therefore, one frog can eat for 18 days because it is only eating .5 a day.
Answer:
The answer is 3.2 E 3 or 3.2 x 10^3
You move back 3 spaces which is 3.2, since you moved back 3 spaces, you put 3 as the power/exponet.
To be more satisfied, 3.2 is your base number, it is the big number Below the power/exponent. The power/exponent is 3, you moved 3 spaces and you moved to the left, so it is represented as a positive power/exponent.
Hope this helps.
Because the shape is a cube, we know that all sides must be 5cm. To find the area of a side, you do base × height, so 5 × 5 = 25. If you look at the net, you'll notice that there are 6 faces, which means you have to do 25 × 6 = 150cm^2. I hope this helps!
<h3><u>Question:</u></h3>
There are 3900 workers in the three main buildings downtown. Twice as many people work in the largest building as in the smallest of the three. There are 500 more workers in the second-largest building than in the smallest building. How many workers are in each building?
<h3><u>Answer:</u></h3>
There are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building
<h3><u>Solution:</u></h3>
Let "b" be the number of workers in smallest building
Given that Twice as many people work in the largest building as in the smallest of the three
number of workers in largest building = 2b
Given that There are 500 more workers in the second-largest building than in the smallest building
Number of workers in second largest building = 500 + b
Given that there are 3900 workers in 3 buildings
b + 2b + 500 + b = 3900
4b + 500 = 3900
4b = 3900 - 500
4b = 3400
b = 850
Thus there are 850 workers in smallest building
workers in largest building = 2b = 2(850) = 1700
workers in second largest building = 500 + b = 500 + 850 = 1350
Thus there are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
